Tetranacci numbers: a(n) = a(n-1) + a(n-2) + a(n-3) + a(n-4) with a(0)=a(1)=a(2)=a(3)=1.
1, 1, 1, 1, 4, 7, 13, 25, 49, 94, 181, 349, 673, 1297, 2500, 4819, 9289, 17905, 34513
1 seqfan posts
Fri Oct 29 05:35:16 CEST 2010 [seqfan] Implementing first 500 sequences in Java