Tribonacci numbers: a(n) = a(n-1) + a(n-2) + a(n-3) with a(0)=0, a(1)=1, a(2)=0.
0, 1, 0, 1, 2, 3, 6, 11, 20, 37, 68, 125, 230, 423, 778, 1431, 2632, 4841, 8904, 16377
1 seqfan posts
Thu Sep 16 19:44:47 CEST 2010 [seqfan] Initial Substrings of n-bit Binary Numbers Not Divisible by k