References to A001592

Hexanacci numbers: a(n+1) = a(n)+...+a(n-5) with a(0)=...=a(4)=0, a(5)=1.
0, 0, 0, 0, 0, 1, 1, 2, 4, 8, 16, 32, 63, 125, 248, 492, 976, 1936, 3840, 7617, 15109


1 seqfan posts

Mon Oct 18 23:16:38 CEST 2010    [seqfan] Re: Convolve tribonacci with trinomials = A099464?

Index of A-numbers in seqfan: by ascending order    by month    by frequency    by keyword
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