Hexanacci numbers: a(n+1) = a(n)+...+a(n-5) with a(0)=...=a(4)=0, a(5)=1.
0, 0, 0, 0, 0, 1, 1, 2, 4, 8, 16, 32, 63, 125, 248, 492, 976, 1936, 3840, 7617, 15109
1 seqfan posts
Mon Oct 18 23:16:38 CEST 2010 [seqfan] Re: Convolve tribonacci with trinomials = A099464?