a(1)=a(2)=1, a(n)=n-a(a(n-1))-a(a(n-2)).
1, 1, 1, 2, 3, 4, 4, 4, 5, 5, 5, 6, 6, 6, 7, 8, 9, 9, 9, 10, 11, 12, 12, 12, 13, 14, 15, 15, 15
1 seqfan posts
Fri Apr 30 13:01:40 CEST 2010 [seqfan] observation about A003160 a(1)=a(2)=1, a(n)=n-a(a(n-1))-a(a(n-2))