Josephus problem: a(2n) = 2a(n)-1, a(2n+1) = 2a(n)+1. 0, 1, 1, 3, 1, 3, 5, 7, 1, 3, 5, 7, 9, 11, 13, 15, 1, 3, 5, 7, 9, 11, 13, 15, 17, 19, 21, 23, 25
2 seqfan posts