References to A019446

a(n) = ceiling(n/tau), where tau=(1+sqrt(5))/2.
1, 2, 2, 3, 4, 4, 5, 5, 6, 7, 7, 8, 9, 9, 10, 10, 11, 12, 12, 13, 13, 14, 15, 15, 16, 17, 17


2 seqfan posts

Thu May 20 13:48:22 CEST 2010    [seqfan] Re: a(n) divides the sum of the first a(n) terms of S
Thu May 20 12:00:47 CEST 2010    [seqfan] Re: a(n) divides the sum of the first a(n) terms of S

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