a(n) = a(n-2) + c(n-1) for n >= 3, a( ) increasing, given a(1)=1, a(2)=3; where c( ) is complement of a( ).
2, 4, 5, 10, 12, 18, 21, 29, 34, 43, 49, 59, 66, 78, 86, 100, 109, 124, 134, 150, 161
1 seqfan posts
Mon Nov 2 01:54:51 CET 2009 [seqfan] Re: Incongruous reordering of N