Write n = m^k with m, k integers, k >= 1, then a(n) = smallest possible choice for m.
1, 2, 3, 2, 5, 6, 7, 2, 3, 10, 11, 12, 13, 14, 15, 2, 17, 18, 19, 20, 21, 22, 23, 24, 5, 26, 3
3 seqfan posts
Sat Sep 4 17:58:26 CEST 2010 [seqfan] Re: A175781: What if n is 6th power (as 64) - n^(1/2)?
Sat Sep 4 17:58:26 CEST 2010 [seqfan] Re: A175781: What if n is 6th power (as 64) - n^(1/2)?
Sat Sep 4 15:12:03 CEST 2010 [seqfan] Re: A175781: What if n is 6th power (as 64) - n^(1/2)?
Index of A-numbers in seqfan: by ascending order
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