Square excess of n: difference between n and largest square <= n.
0, 0, 1, 2, 0, 1, 2, 3, 4, 0, 1, 2, 3, 4, 5, 6, 0, 1, 2, 3, 4, 5, 6, 7, 8, 0, 1, 2, 3, 4, 5, 6, 7, 8
1 seqfan posts
Mon Jan 5 21:24:53 CET 2009 [seqfan] Re: n^3 - (largest square < n^3)