Congrua (possible solutions to the congruum problem): numbers n such that there are integers x, y and z with n = x^2-y^2 = z^2-x^2.
24, 96, 120, 240, 336, 384, 480, 720, 840, 960, 1320, 1344, 1536, 1920, 1944, 2016
1 seqfan posts
Wed Nov 12 13:21:12 CET 2008 [seqfan] Re: a Diophantine equation