a(1)=1, a(2)=3; then append digits of a(n-1)*a(n).
1, 3, 3, 9, 2, 7, 1, 8, 1, 4, 7, 8, 8, 4, 2, 8, 5, 6, 6, 4, 3, 2, 8, 1, 6, 4, 0, 3, 0, 3, 6, 2, 4, 1
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Mon Aug 8 12:14:12 CEST 2011 [seqfan] Summer sequence boot camp : adding digits to the right... and more