Generated by recursion: a(n)=Mod[Prime[n+1],Prime[n]]*n[n-1]; a[0]=1; Product of the first n consecutive prime-differences.
1, 2, 4, 16, 32, 128, 256, 1024, 6144, 12288, 73728, 294912, 589824, 2359296
2 seqfan posts
Sun Jun 13 08:51:05 CEST 2010 [seqfan] Re: (3^n+1)/2 is prime, A171381