a(0)=1, for n>=1 a(n)=sum(k=0,n,10^k*N(n,k)) where N(n,k) =1/n*C(n,k)*C(n,k+1) are the Narayana numbers (A001263).
1, 1, 11, 131, 1661, 22101, 305151, 4335711, 63009881, 932449961, 14004694451
1 seqfan posts
Fri Feb 18 14:28:55 CET 2011 [seqfan] More results on Basket Weave tiling paths