a(n) = floor(n/a(floor(n/2))); a(1) = 1.
1, 2, 3, 2, 2, 2, 2, 4, 4, 5, 5, 6, 6, 7, 7, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 8, 8, 8
1 seqfan posts
Thu Mar 3 07:14:25 CET 2011 [seqfan] Re: Bivariate recurrence leading to univariate one with sqrt()