Secondary diagonal of triangle A100235 divided by row number: a(n) = A100235(n+1,n)/(n+1) for n>=0.
1, 4, 21, 109, 566, 2939, 15261, 79244, 411481, 2136649, 11094726, 57610279
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Sun Jan 11 23:36:02 CET 2009 [seqfan] Index of linear recurrences