a(0) = 1; a(n+1) = Sum_{k, 0<=k<=n} a(k)*A001147(n-k), where A001147 = double factorial numbers.
1, 1, 2, 6, 26, 158, 1282, 13158, 163354, 2374078, 39456386, 737125446
1 seqfan posts
Tue Aug 9 01:53:00 CEST 2011 [seqfan] Re: Constant Arising from a Certain Functional Eq