References to A119558

a(1)=0,a(2)=0,a(3)=1 then a(n)=abs(a(n-1)-a(n-2))+(-1)^n*a(n-3).
0, 0, 1, 1, 0, 2, 1, 1, 2, 4, 5, 1, 2, 8, 7, 3, 4, 14, 15, 3, 4, 22, 21, 5, 6, 32, 33, 5


4 seqfan posts

Tue Feb 28 04:01:24 CET 2012    [seqfan] Re: A119558 -- FIXED
Mon Feb 27 15:20:31 CET 2012    [seqfan] Re: A119558 -- FIXED
Mon Feb 27 15:12:10 CET 2012    [seqfan] Re: A119558 -- FIXED
Mon Feb 27 15:05:29 CET 2012    [seqfan] A119558

Index of A-numbers in seqfan: by ascending order    by month    by frequency    by keyword
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