Numerator of the first convergent to the sqrt(n) using the recursion x = (n/x+x)/2.
1, 3, 2, 5, 3, 7, 4, 9, 5, 11, 6, 13, 7, 15, 8, 17, 9, 19, 10, 21, 11, 23, 12, 25, 13, 27, 14
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Sun May 1 12:06:41 CEST 2011 [seqfan] Re: A new digital problem