a(n)=floor(b(n)), where b(0)=1, b(n)=b(n-1)^2-n^b(n-1).
1, 0, 1, 0, 3, 4, 2092, 437258
3 seqfan posts
Sat Nov 27 19:58:25 CET 2010 [seqfan] Re: verifying A153063 with a(n)=a^2-n^a
Sat Nov 27 16:14:22 CET 2010 [seqfan] Re: verifying A153063 with a(n)=a^2-n^a
Sat Nov 27 16:04:09 CET 2010 [seqfan] verifying A153063 with a(n)=a^2-n^a
Index of A-numbers in seqfan: by ascending order
by month
by frequency
by keyword
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