a(1)=1. a(n) = the smallest positive integer such that d(a(n)) = d(sum{k=1 to n} a(k)), where d(m) = the number of divisors of m.
1, 2, 2, 2, 8, 2, 2, 8, 2, 2, 8, 2, 2, 8, 2, 21, 5, 6, 6, 15, 3, 6, 8, 6, 2, 10, 12, 6, 12, 2, 10
7 seqfan posts
Thu May 28 23:16:07 CEST 2009 [seqfan] Re: d(a(n)) = d(a(n)-a(n-1))
Thu May 28 22:14:12 CEST 2009 [seqfan] d(a(n)) = d(a(n)-a(n-1))
Thu May 28 13:57:48 CEST 2009 [seqfan] Re: d(a(n)) = d(a(n)-a(n-1))
Thu May 28 13:57:48 CEST 2009 [seqfan] Re: d(a(n)) = d(a(n)-a(n-1))
Thu May 28 13:57:48 CEST 2009 [seqfan] Re: d(a(n)) = d(a(n)-a(n-1))
Thu May 28 13:57:47 CEST 2009 [seqfan] Re: d(a(n)) = d(a(n)-a(n-1))
Sun May 24 15:55:31 CEST 2009 [seqfan] d(a(n)) = d(a(n)-a(n-1))
Index of A-numbers in seqfan: by ascending order
by month
by frequency
by keyword
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