Start with a(1) = 1 then a(n) = smallest number > a(n-1) such that a(n) divides concat(a(1), a(2), ..., a(n)).
1, 2, 3, 5, 10, 12, 15, 20, 25, 30, 39, 44, 50, 100, 101, 125, 150, 188, 200, 220, 230
2 seqfan posts
Thu Oct 14 19:30:21 CEST 2010 [seqfan] Re: a(n) divides concat(a(1) ... a(n))