Unmatter combinations as pairs of quarks (q) and antiquarks (a), for q >= 1 and a >= 1. Each combination has n = q+a >= 2 quarks and antiquarks which preserve the colorless. - if n = 2, we have: qa (biquark - for example mesons and antimesons), so the pair is (1,1); - if n = 3 we have no unmatter combination, so the pair is (0,0); - if n = 4, we have qqaa, the pair is (2,2); - if n = 5, we have qqqqa, qaaaa, so the pairs are (4,1) and (1,4); - if n = 6, we have qqqaaa, whence (3,3); - if n = 7, we have qqqqqaa, qqaaaaa, whence (5,2),(2,5); - if n = 8, we have qqqqqqqa, qqqqaaaa, qaaaaaaa, whence (7,1),(4,4),(1,7); - if n = 9, we have qqqqqqaaa, qqqaaaaaa, whence (6,3),(3,6); - if n = 10, we have qqqqqqqqaa, qqqqqaaaaa, qqaaaaaaaa, whence (8,2), (4,4), (2,8).
1, 1, 0, 0, 2, 2, 4, 1, 1, 4, 3, 3, 5, 2, 2, 5, 7, 1, 4, 4, 1, 7, 6, 3, 3, 6, 8, 2, 5, 5, 2,
2 seqfan posts
Sun Nov 7 19:08:37 CET 2010 [seqfan] Re: physics