> f(0) = 0
> f(n) = f(n-1) - 1/n if >= 0, else f(n-1) + 1/n.
>
> For which n do we have f(n-2) > f(n-1) > f(n)?
I get
3 6 13 34 91 264 783 2342 7013 21030 63079 189236 567709 1703124
5109367 15328088 45984249
Since odds and evens alternate, I conclude that no term is triple
the previous.
--
Don Reble djr at nk.ca