[seqfan] Re: 0, 2, 3, ?
Vladimir Shevelev
shevelev at bgu.ac.il
Fri Jan 2 10:44:17 CET 2015
There is no a next number. Indeed n-1 divides n^n-1=(n-1)(n^(n-1)+...+1),
so n^n+1==2 (mod (n-1)).
Vladimir
________________________________________
From: SeqFan [seqfan-bounces at list.seqfan.eu] on behalf of юрий герасимов [2stepan at rambler.ru]
Sent: 28 December 2014 18:36
To: seqfan at list.seqfan.eu
Subject: [seqfan] 0, 2, 3, ?
Dear SeqFans,
Numbers n such that n - 1 divides n^n + 1: 0, 2, 3, ... What in the next ( > 3*10^5 ) one ?
Best regards. JSG
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