[seqfan] Re: Question from Karol Penson
Max Alekseyev
maxale at gmail.com
Wed Jun 3 17:20:21 CEST 2015
A straightforward formula for the coefficient of x^n in [1-(1-x)^(1/m)]^p:
\sum_{i=0}^p \binom{p}{i} \binom{i/m}{n} (-1)^{i+n}
Regards,
Max
On Wed, Jun 3, 2015 at 4:18 PM, penson at lptl.jussieu.fr <
penson at lptl.jussieu.fr> wrote:
> Assume p=2,3,... and m=2,3.... .
> Does anyone know a quick way to obtain the coefficient of x^n in the
> expansion of
>
> [1-(1-x)^(1/m)]^p
>
> as a function of p and m ?
>
> Thanks,
>
> Karol Penson
>
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