[seqfan] Re: Divisors of the concatenation of n+1 and n
Eric Angelini
Eric.Angelini at kntv.be
Wed Jun 3 23:45:04 CEST 2015
Merci beaucoup, Reinhard !
:-D
Regards,
É.
Catapulté de mon aPhone
> Le 3 juin 2015 à 15:29, Reinhard Zumkeller <reinhard.zumkeller at gmail.com> a écrit :
>
> https://oeis.org/draft/A256285
> Best
> R.
>
>
> 2015-06-03 11:48 GMT+02:00 Eric Angelini <Eric.Angelini at kntv.be>:
>
>> Hello SeqFans,
>> t(n) is the smallest unused integer so far in T such that t(n) is a
>> divisor of the concatenation of n+1 and n.
>>
>> n = 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16
>> 17 18 19 20 21 22
>> concat = 21 32 43 54 65 76 87 98 109 1110 1211 1312 1413 1514 1615 1716
>> 1817 1918 2019 2120 2221 2322
>> T = 1, 2 43, 3, 5, 4,29, 7,109, 6, 173, 8, 9, 757, 17, 11,
>> 23, 14, 673, 10, 2221, 18,...
>>
>> Example:
>> The divisors of 1413 (concatenation of 14 and 13) are 1, 3, 9, 157, 471
>> and 1413. As 1 and 3 appear already in T, we have t(13) = 9.
>>
>> Is T a permutation of the integers > 0 ?
>>
>> Best,
>> É.
>>
>>
>>
>> _______________________________________________
>>
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>
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