[seqfan] Re: CF for Constant A071873
Hans Havermann
gladhobo at teksavvy.com
Sun May 10 09:13:23 CEST 2015
> contfrac(x) = [0, 1, 1, 48, 1, 9182736455463727, 4, 1, 2, 1, 3, 1,
> 16413861141941053151166388889231063606316227031696978138434,
> 9, 9, 2, 1, 3, 8, 1, 1, 19, 1, 1, 2, 3, 1, 7, 1, 1, 4, 1, 1, 1,
> 3, 3, 1, 1, 2, 2, 2, 1, 5, 2, 1, 1, 1, 1, 5, 1, 78, 1, 21, 1, 1, 5, 3, 2]
>
> but 50,000 digits of x will not yield more partial quotients!
Naively using the sequence's Mathematica code, even 1000 digits will you you more quotients; but one needs to be careful. Here are the number of digits in that next, large quotient based on a given, starting number of decimal digits:
10^3 805
10^4 9806
10^5 99805
I’ll let this run for a few hours to see if it stabilizes.
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