[seqfan] Convert/concatenate/divide

[jnthn stdhr]

For n > 0, covert n to its binary representation b, then let x equal the
concatenation of the decimal values of each power of two <= n muliplied by
its associated bit in b. If n divides x  a(n) = n. For example, with n=18,
b=10010, x = concat(16,0,0,2,0) = 160020, and 160020 / 18 = 8890, so 18 is
in the sequence. The sequence begins:  1, 2, 3, 4, 6, 8, 9, 10, 12, 16, 18,
20, 24, 27, 30, 32, 36, 40, 48, 60, 64, 72, 80, 90, 96, 100, 112, 120, 128,
130, 144, 160, 180, 184, 190, 192, 200,...

This first differs from A002183 (Number of divisors of n-th highly
composite number.) a(14)=27. 84 is the first number that is a term in A2183
that is not in this sequence.

Should I add this?

-Jonathan