sequence terminating with 384 billion digits

[David Broadhurst]

            A finite sequence, ending with 384 billion digits
            -------------------------------------------------

The odd-greedy egyptian-fraction algorithm for

                         5/1444613

has 37 terms. 

The last fraction is 1/N, where the integer N has

                        384,122,451,172

decimal digits. To 50-digit precision:

  N = 3.4138246747280898204290555148642392302131725843319*10**(384122451171)

The sequence of remainder-numerators is:

          5,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20,
          21,22,23,24,25,26,27,28,29,30,31,32,33,34,43,64,1

David Broadhurst

CC: David Bailey and Stan Wagon