Michael Somos wrote: > %F A018805 a(n) = 2 ( Sum phi(j), j=1..n ) - 1; a(n) = n^2 - Sum a([n/j]), > j=2..n. > %A A018805 David W. Wilson (wilson at ctron.com) Isn't a(n) = n^2 - Sum (j = 2..n, a([n/j])) a cute recurrence?