A054770
Jud McCranie
jud.mccranie at mindspring.com
Wed Jun 7 21:13:44 CEST 2000
At 10:24 AM 6/7/00 -0400, John Conway wrote:
I think that's an unhelpful remark. There's no universally
>agreed "start" to either sequence. What IS universally agreed is
>the numbering of the two sequences:
>
> n 0 1 2 3 4 5 6 7 8 ...
> Fn 0 1 1 2 3 5 8 13 21 ...
> Ln 2 1 3 4 7 11 18 29 47 ...
>
>so that all you mean is that you prefer to start the Fibonacci
>sequence at the terms F2, F3 and the Lucas one at L1, L2.
Sorry, actually I made a typo, I meant for the Fibonacci sequence to start
1,1 (not 1,2 as I typed).
> I'm sure many people would prefer to start the Fibonacci one
>with F1,F2, while others prefer to include the n=0 terms. I'm
>sure most mathematicians (myself included) don't think it sensible
>to choose any fixed start.
I understand what is meant by the zeroth term, but A54770 clearly states
that it is using 1,3,4 (A204), not 2,1,3,4 (A32):
%S A054770
2,6,9,13,17,20,24,27,31,35,38,42,46,49,53,56,60,64,67,71,74,78,82,85,
%T A054770
89,93,96,100,103,107,111,114,118,122,125,129,132,136,140,143,147,150,
%U A054770 154,158,161,165,169,172,176,179,183,187,190,194,197,201,205,208,212
%N A054770 Not the sum of distinct Lucas numbers 1,3,4,7,11 ... (A000204).
%O A054770 0,1
%K A054770 nonn,easy
%Y A054770 Cf. A003263.
+--------------------------------------------------------+
| Jud McCranie |
| |
| 137*2^261147+1 is prime! (78,616 digits, 5/2/00) |
+--------------------------------------------------------+
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