Riffs & Rotes & A061396
David W. Wilson
wilson at aprisma.com
Thu Jun 21 00:08:58 CEST 2001
Jon Awbrey wrote:
>
> ¤~~~~~~~~~¤~~~~~~~~~¤~~~~~~~~~¤~~~~~~~~~¤~~~~~~~~~¤
>
> Hello, I am new to the SeqFan list. I would like
> to report on some work that I did as a beginning
> and continuing graduate student in the years from
> 1976 to 1986. Since this is not currently my area
> of active work, I am afraid that I will have to be
> somewhat dependent on my old notes, such as I find
> them. I tried to organize this stuff in a logical
> order, but that was hopeless, so I will just have
> to take things up in a somewhat random order.
>
> So let me introduce the sequence formally known as "A061396".
>
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>
> Riffs & Rotes
>
> 1, 2, 6, 20, 73, 281, 1124, 4488
>
> ¤~~~~~~~~~¤~~~~~~~~~¤~~~~~~~~~¤~~~~~~~~~¤~~~~~~~~~¤
>
> ID: A061396
>
> Seq: 1,1,2,6,20,73,281,1124,4488
>
> Name: Number of "rooted index-functional forests" (Riffs) on n nodes.
> Number of "rooted odd trees with only exponent symmetries" (Rotes)
> on 2n+1 nodes.
>
> Ref: J. Awbrey, personal journal, circa 1978.
> Letter to N. J. A. Sloane, 1980-Aug-04.
>
> Formula: G.f. A(x) = 1 + x + 2*x^2 + 6*x^3 + ... satisfies
> A(x) = Product_{j = 0 to infinity} (1 + x^(j+1)*A(x))^a_j.
>
> Example: These structures come from recursive primes factorizations
> of natural numbers, where the recursion proceeds on both
> the exponents (^k) and the indices (_k) of the primes
> invoked in the factorization:
>
> 2 = (prime_1)^1 = (p_1)^1, briefly, p, weight = 1 node => a(1) = 1.
> 3 = (prime_2)^1 = (p_2)^1, briefly, p_p, weight = 2 nodes and
> 4 = (prime_1)^2 = (p_1)^2, briefly, p^p, weight = 2 nodes => a(2) = 2.
>
> Keys: nice,nonn,new,easy,more
>
> Offset: 0
>
> Author: Jon Awbrey (jawbrey at oakland.edu), Jun 09 2001
I computed this sequence from the g.f. I get
1 1 2 6 20 73 281 1124 4618 19387 82765 358245 1568458 6933765 30907194
138760603 626898401 2847946941 13001772692 59618918447 274463781383
1268064807513 5877758071073 27325789133590 127384553287387 595318140045752
My a(8) = 4618 disagrees with the published a(8) = 4488. I computed the
sequence using two programs, with the same result, and I am pretty sure
it is correct (some corroboration would be welcomed). In defense of my
value, notice that the relative differences of my terms increase nicely:
1/1 = 1.000000
2/1 = 2.000000
6/2 = 3.000000
20/6 = 3.333333
73/20 = 3.650000
281/73 = 3.849315
1124/281 = 4.000000
4618/1124 = 4.108541
19387/4618 = 4.198138
82765/19387 = 4.269098
358245/82765 = 4.328460
1568458/358245 = 4.378171
6933765/1568458 = 4.420753
30907194/6933765 = 4.457491
whereas a(8) = 4488 produces a sudden decrease of the relative difference,
which would be unexpected in this context.
1/1 = 1.000000
2/1 = 2.000000
6/2 = 3.000000
20/6 = 3.333333
73/20 = 3.650000
281/73 = 3.849315
1124/281 = 4.000000
4488/1124 = 3.992883
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