Biquanimous numbers

[John Layman]

> David W. Wilson:  So, let's call a number biquanimous if its digits can be
> split into two sets with the same sum.

I have calculated the number of n-digit base-3 biquams for n=1..12 and find that
the numbers agree with the first 12 terms of A053152.  

The number of n-digit base-4 biquams, for n=1..9, are
0,3,18,91,420,1829,7686,31623,128520,...   I have submitted this sequence to the
EIS.