Jon Perry wrote:
> In Formula:
>
> a(n) = 3*(a(n-1)-1) + 2^n.
>
> should read:
>
> a(n) = 3*a(n-1) + 2^(n-1)
True. But if we want a recurrence relation, why not get rid of the 2^(n-1),
and say
a(n) = 5 a(n-1) - 6 a(n-2)?
Dean Hickerson
dean at math.ucdavis.edu