A010815 convolution inverse?

Christian G.Bower bowerc at usa.net
Wed Jun 12 19:18:17 CEST 2002

Dean Hickerson <dean at math.ucdavis.edu> wrote:
> Aren't you confusing "inverse" with "square root"?  A010815 and A000041
> convolutional inverses, since the product of the corresponding Taylor
> is 1.

We should probably avoid the phrase "convolutional inverse" altogether
since there is that potential to interpret "inverse" as reciprocal or as
"undoing the operation."

More information about the SeqFan mailing list