> %N A060277 Number of m for which a+b+c = n; abc = m has two distinct
> solutions (a,b,c) with 1<=a<=b<=c.
Agreed, but write "has at least two distinct". (Because
39=4+5+20=5+10+24=6+8+25, and 1200=4*5*20=5*10*24=6*8*25;
and that is one of the nine solutions for a(39).)
--
Don Reble djr at nk.ca