Sequence idea

[Richard Guy]

The corresponding sequence for real fields is

1,4,9,16,25,36,49,64,81,100,

I believe.  But Hugh Williams has just noted that
a far more interesting sequence would be the
largest such  k.  He says that Duncan Buell
(duncan at super.org) may know the answer to
this, up to the hundreds.    R.

On Wed, 26 Feb 2003, David Wilson wrote:

> Smallest k such that Q(sqrt(-k)) has class number n.
> For n = 1 through 10, i think we get 1,5,23,14,47,26,71,41,199,74
> I don't have the machinery to extend this one
> I don't even know if the domain is N.
> 
> Also, the analogous sequence for Q(sqrt(n)) would be good.