a/b + b/c + c/a = n

[Hans Havermann]

On Friday, July 11, 2003, at 02:58  PM, <all at abouthugo.de> wrote:

> I had set the threshold for accepting a sum being equal to the nearest 
> integer to 10^(-9)
> and the 3 wrong solutions (=4) all had absolute differences < 10^-9. 
> Can someone with access to higher precision software improve my 
> results?

I think your (=7) results are wrong as well. Can it be shown that, as a 
minimum, all solutions require (a*b*c) to be a cube?