Convolution Sum Over Divisors
Leroy Quet
qq-quet at mindspring.com
Mon Aug 16 15:41:32 CEST 2004
Let a(1) = 1.
Let, for m >= 2, a(m) =
sum{k|m, k<m} a(k) a(m-k),
where the sum is over the positive PROPER divisors, k, of m.
(We can also define a(0) = 0, and take the sum over every positive
divisor of m.)
So, we have
(0), 1, 1, 1, 2, 2, 5, 5, 14, 19, 37, ...
What else can be said about this sequence?
(I do not believe it is in the EIS yet.)
thanks,
Leroy Quet
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