GCD(k,j) Product
Leroy Quet
qq-quet at mindspring.com
Tue Feb 3 04:52:50 CET 2004
Analogous to sequence A018806, but with the double sum replaced with a
double product,
we can have the sequence:
a(n) =
product{k=1 to n} product{j=1 to n} GCD(k,j),
which begins, I believe:
1, 2, 6, 96, 480,...,
which is not in the EIS.
Am I right to assume that:
limit{n-> oo} a(n)^(1/n^2) =
exp(-zeta'(2)/zeta(2)) ?
(where zeta(2) = pi^2/6,
and zeta'(2) is the derivative of the Riemann zeta function at 2)
thanks,
Leroy Quet
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