Rép. : Re: numerator of function is prime

[Mohammed BOUAYOUN]

fo many hours pari don't find any factors.
and I suppose that numerator(796) is prime.

are there any algorithm or methods to verify quickly this number.

Thanks


>>> "Kennedy" <kennedy at oldnews.org> 02/16 5:47  >>>

If pp(796) = f(796), where f is the sum you give,
then Mathematica claims the numerator of pp(796)
is prime. However, I seem to remember reading
somewhere that Mathematica's PrimeQ predicate
is not 100% reliable.

Kennedy
----- Original Message ----- 
From: Mohammed BOUAYOUN 
To: seqfan at ext.jussieu.fr 
Sent: Monday, February 16, 2004 10:32 AM
Subject: numerator of function is prime


I defined a new function f(n)=sum(i=1,n,prime(i)/prime(i+1))
Example  
f(1)=2/3
f(2)=2/3 + 3/5
f(3)=2/3+3/5+5/7
f(4)=2/3+3/5+5/7+7/11

can anyone verify if numerator(pp(796)) is prime

thanks
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