numerator of function is prime

[Kennedy]

If pp(796) = f(796), where f is the sum you give,
then Mathematica claims the numerator of pp(796)
is prime. However, I seem to remember reading
somewhere that Mathematica's PrimeQ predicate
is not 100% reliable.

Kennedy
  ----- Original Message ----- 
  From: Mohammed BOUAYOUN 
  To: seqfan at ext.jussieu.fr 
  Sent: Monday, February 16, 2004 10:32 AM
  Subject: numerator of function is prime


  I defined a new function f(n)=sum(i=1,n,prime(i)/prime(i+1))
  Example  
  f(1)=2/3
  f(2)=2/3 + 3/5
  f(3)=2/3+3/5+5/7
  f(4)=2/3+3/5+5/7+7/11

  can anyone verify if numerator(pp(796)) is prime

  thanks
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