Sequential Squares -- A005842
Ed Pegg Jr
edp at wolfram.com
Tue Mar 30 18:55:18 CEST 2004
One comment on the new wording.
If a solution exists for ceiling(sqrt(sum(k^2, {k,1,n}))), then that's
a proof. All entries labeled "solvable" have been proved by
demonstration.
It should be straightforward to prove everything under n=26 is
correct.
n=23 is definitely 66, not 67. Proof: http://www.mathpuzzle.com/seq23.gif
n=26 and n=28 will be difficult to prove, and likely need long brute-force
computer searches.
n=32, 33, and 34 can likely be proved in some elegant manner, OR they
will have fantastically elegant solutions.
n=36 has been solved (I think by Friedman).
I'll make a page about all of this, and will include all of the known
solutions.
--Ed Pegg Jr.
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