m^j + (m+1)^k = prime
Leroy Quet
qq-quet at mindspring.com
Tue Mar 30 21:36:50 CEST 2004
f.firoozbakht at sci.ui.ac.ir wrote:
>The " lowest positive integers such that m^j+(m+1)^k=a prime =a(m) "
>isn't well defined.
>For example take m=12, 12^1+13^2 and 12^2+13^1 are both primes now
>by your definition we don't know a(12)=12^1+13^2 or a(12)=12^2+13^1,
>You wrote " 157 "or 12^2+13^1 as a(12),I think it is better that
>a(m) is defined :
>"smallest prime of the for m^j+(m+1)^k where j and k are positive
>integers.
Right. I meant the smallest prime of the form.
thanks,
Leroy Quet
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