m^j + (m+1)^k = prime

Leroy Quet qq-quet at mindspring.com
Tue Mar 30 21:36:50 CEST 2004

f.firoozbakht at sci.ui.ac.ir wrote:
>The " lowest positive integers such that m^j+(m+1)^k=a prime =a(m) "
>isn't well defined.
>For example take m=12, 12^1+13^2 and 12^2+13^1 are both primes now 
>by your definition we don't know a(12)=12^1+13^2 or a(12)=12^2+13^1,
>You wrote " 157 "or 12^2+13^1 as a(12),I think it is better that 
>a(m) is defined :
>"smallest prime of the for m^j+(m+1)^k where j and k are positive 

Right. I meant the smallest prime of the form.

Leroy Quet

More information about the SeqFan mailing list