[SeqFan] Re: Number of unrestricted divisor chains

[Richard Guy]

In partial reply to another comment of
Eugene McDonnell, a divisor chain can't
start with  1.  If it starts with  2  it
would have to be  2 1 3 6 4 or 12  and if
it starts with  3  then  3 1 2 6 4 or 12;
or 3 1 4 2 5 or 10; or 3 1 4 8 2 or 16
so they're less numerous.   R.

On Tue, 11 May 2004, Jud McCranie wrote:

> At 01:44 PM 5/11/2004, Eugene McDonnell wrote:
> >The number of divisor chains having any first digit:
> >
> >k    1 2 3 4 5 6 7 8  9 10 11 12 13 
> >14  15  16  17  18  19   20   21  22   23    24
> >a(k) 1 1 2 2 4 5 7 7 24 22 29 39 67 55 386 235 312 347 451 1319 5320 3220 
> >4489 20237
> 
> I could supply these up to n=35 (I would have to recalculate them, though).
> 
> 
> 
>