Roots of (x+1)^n - x^2n = 0

[cino hilliard]

Hi, Emeric


>What about extracting n-th root on both sides of (x+1)^n = x^2n ?
>Emeric
Indeed, x+1 = x^2 or x^2 - x  - 1 = 0 has the the 2 real roots. I should 
have figured that out.

Thanks
Cino