A014577

[Simon Plouffe]

Hello,


just this note :


If we have : 2*sum( 1/2^(2^n), n=0 to infinity) = a =

1.63284301804378628741615947506105044340662275184110560868242180768611122838\ 
 
911060012097062649679453123511768709641586786498668506277004740694033718\ 
 
360632500328275763901107944227242740384656904685662468220603154932375397\ 
 
013312181755191547121771854165113419223023206511672202906825456190450605\

It also have these 2 expansions:

a = 1 + 1/2 + 1/(2*4) + 1/(2*4*16) + 1/(2*4*16*256) + 
1/(2*4*16*256*65536)+ ...

a = 1 + 1/2 + 1/8 + 1/128 + 1/32768 + 1/2147483648 + ...

I guess this is known too.

Simon Plouffe