Divisible by 12: a^3 + b^3 = c^2

[Pfoertner, Hugo]

-----Original Message-----
From: Pfoertner, Hugo [mailto:Hugo.Pfoertner at muc.mtu.de] 
Sent: Thursday, October 21, 2004 11:08
To: 'Ed Pegg Jr'
Cc: seqfan
Subject: RE: Divisible by 12: a^3 + b^3 = c^2

[...]
we get a sequence

Numbers n such that 12*n^2 can be expressed as the sum of the cubes of two
primes:             ^^^^^^

OOPS ... should be: (12*n)^2  (or 144*n^2)


19 67695 411292 1134035 1184876 2112836 2455255 4073384 11293009
16171470 18589912 34388501 63609329 63711615 117446600 166530856

Hugo