2, 1, 3, 2, 4, 3, 5, 4, 6, 5, 7, 6, 8, 7, 9, 8, 10, 9, . . .
N. J. A. Sloane
njas at research.att.com
Thu Oct 28 22:24:20 CEST 2004
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Henry, that's A028242 (did you look?), and the recurrence
is there too.
Neil
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