A094943
Gottfried Helms
Annette.Warlich at t-online.de
Thu Aug 25 19:20:59 CEST 2005
Another surprising(?) coincidence ...
I'm currently looking at sequences, which arise from rules
like
(a + b)^n + (a - b)^n
-----------------------------
2
where a is usually an integer, or a fraction and b may be an irrational
or even an imaginary number. Such rules produce known sequences
of recurrence-order two, interesting patterns of prime-factorizations,
and I thought to try some generalization.
My current generalization is, to view +b and -b in the above
terms as b*w0 and b*w1, where w0 and w1 are the two complex square-roots
of 1 (=1 and -1),
and to consider cases of higher complex roots. An extended case of order 3
could be ( w = (-1 + sqrt(2)+i)/2, (w0=w^0,w1=w, w2 = w^2 )
(a + b + c)^n + (a + b*w1 + c*w2)^n + (a + b*w2 + c*w4)^n
--------------------------------------------------------------
3
which leads to real numbers for all n>0, and for proper selection of a,b,c
it also produces an integer sequence, like in the case of order 2 the
known Fibonacci and Lucas-sequences.
The generalization looks like (for order p)
_p-1 ( _ p-1 ) n
\ ( \ )
) ( ) (a_i * w ^ij) )
/_ ( /_ )
j=0 ( i=0 )
Anyway - the numbers I got for the first parameters (a,b,c)=(1,2,3)
of order 3 are just the numbers of the sequence A094943 . Maybe that is of
interest; for me this connection seems to be useful, since to compute
the coefficients of the resulting real terms is a bit tedious.
If the matrix-method given in the example below can be extended to higher
order, then this would be a much more handy rule to compute the coefficients
than to employ a symbolic algebra program and evaluate the nominator for
higher orders ...
Gottfried Helms
ID Number: A094943
URL: http://www.research.att.com/projects/OEIS?Anum=A094943
Sequence: 1,13,72,429,2601,15534,93339,559845,3359232,20155473,
120932109,725594598,4353563943,26121388761,156728328192,
940369966965,5642219821473,33853318876350,203119913356515,
1218719480001309
Name: A sequence generated from a semi-magic square.
Comments: The 3 rows: 1 3 2, 2 1 3, and 3 2 1 form a semi-magic square; with rows,
columns and a diagonal having a sum of 6. a(n)/a(n-1) tends to 6, an
eigenvalue of the matrix. E.g.: a(7)/a(6) = 93339/15534 = 6.0086...
A094944 uses the same format and operations but has different terms.
Formula: Let [1 3 2 / 2 1 3 / 3 2 1] = the 3 X 3 matrix M. Take M^n * [1 0 0] = [p q r]; then a(n) =
p.
Example: a(4) = 429 since M^4 * [1 0 0] = [429 q r]
Math'ca: a[n_] := (MatrixPower[{{1, 3, 2}, {2, 1, 3}, {3, 2, 1}}, n].{{1}, {0},
{0}})[[1, 1]]; Table[ a[n], {n, 10}] (from Robert G. Wilson v May 29
2004)
See also: Cf. A094944.
Adjacent sequences: A094940 A094941 A094942 this_sequence A094944
A094945 A094946
Sequence in context: A096913 A026916 A106173 this_sequence A000470
A107141 A097460
Keywords: nonn
Offset: 1
Author(s): Gary W. Adamson (qntmpkt(AT)yahoo.com), May 25 2004
Extension: Edited and extended by Robert G. Wilson v (rgwv(AT)rgwv.com), May 29
2004
S
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